3(x-2)=(2x-1-0)

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Solution for 3(x-2)=(2x-1-0) equation: 



3(x-2)=(2x-1-0)

We move all terms to the left:

3(x-2)-((2x-1-0))=0

We add all the numbers together, and all the variables

3(x-2)-((2x-1))=0

We multiply parentheses

3x-((2x-1))-6=0



We calculate terms in parentheses: -((2x-1)), so:

(2x-1)

We get rid of parentheses

2x-1

Back to the equation:

-(2x-1)



We get rid of parentheses

3x-2x+1-6=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5

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