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3(x-2)/9=2(x+1)/12
We move all terms to the left:
3(x-2)/9-(2(x+1)/12)=0
We calculate fractions
3x/()+(-(2(x+1)*9)/()=0
We calculate terms in parentheses: +(-(2(x+1)*9)/(), so:We get rid of parentheses
-(2(x+1)*9)/(
We multiply all the terms by the denominator
-(2(x+1)*9)
We calculate terms in parentheses: -(2(x+1)*9), so:We get rid of parentheses
2(x+1)*9
We multiply parentheses
18x+18
Back to the equation:
-(18x+18)
-18x-18
Back to the equation:
+(-18x-18)
3x/()-18x-18=0
We multiply all the terms by the denominator
3x-18x*()-18*()=0
We add all the numbers together, and all the variables
3x-18x*()=0
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