3(x-2)/4=(x+2)/6-3

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Solution for 3(x-2)/4=(x+2)/6-3 equation: 



3(x-2)/4=(x+2)/6-3

We move all terms to the left:

3(x-2)/4-((x+2)/6-3)=0

We calculate fractions


(18x-36)/()+(-((x+2)*4)/()=0



We calculate terms in parentheses: +(-((x+2)*4)/(), so:

-((x+2)*4)/(

We multiply all the terms by the denominator


-((x+2)*4)



We calculate terms in parentheses: -((x+2)*4), so:

(x+2)*4

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We get rid of parentheses

-4x-8

Back to the equation:

+(-4x-8)



We get rid of parentheses

(18x-36)/()-4x-8=0

We multiply all the terms by the denominator


(18x-36)-4x*()-8*()=0

We add all the numbers together, and all the variables

(18x-36)-4x*()=0

We get rid of parentheses

18x-4x*()-36=0

We move all terms containing x to the left, all other terms to the right

18x-4x*()=36

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