3(x-2)-8=6(x-20+16

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Solution for 3(x-2)-8=6(x-20+16 equation: 



3(x-2)-8=6(x-20+16

We move all terms to the left:

3(x-2)-8-(6(x-20+16)=0

We add all the numbers together, and all the variables

3(x-2)-(6(x-4)-8=0

We multiply parentheses

3x-(6(x-4)-8-6=0

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