3(x-2)-7=-5(-3x+1)-6x

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Solution for 3(x-2)-7=-5(-3x+1)-6x equation: 



3(x-2)-7=-5(-3x+1)-6x

We move all terms to the left:

3(x-2)-7-(-5(-3x+1)-6x)=0

We multiply parentheses

3x-(-5(-3x+1)-6x)-6-7=0



We calculate terms in parentheses: -(-5(-3x+1)-6x), so:

-5(-3x+1)-6x

We add all the numbers together, and all the variables

-6x-5(-3x+1)

We multiply parentheses

-6x+15x-5

We add all the numbers together, and all the variables

9x-5

Back to the equation:

-(9x-5)



We add all the numbers together, and all the variables

3x-(9x-5)-13=0

We get rid of parentheses

3x-9x+5-13=0

We add all the numbers together, and all the variables

-6x-8=0

We move all terms containing x to the left, all other terms to the right

-6x=8

x=8/-6

x=-1+1/3

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