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3(x-2)-5=4(2x+1+5
We move all terms to the left:
3(x-2)-5-(4(2x+1+5)=0
We add all the numbers together, and all the variables
3(x-2)-(4(2x+6)-5=0
We multiply parentheses
3x-(4(2x+6)-5-6=0
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