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3(x-2)-5(2x-1)+2(3x+4)+10=-x
We move all terms to the left:
3(x-2)-5(2x-1)+2(3x+4)+10-(-x)=0
We add all the numbers together, and all the variables
3(x-2)-5(2x-1)+2(3x+4)-(-1x)+10=0
We multiply parentheses
3x-10x+6x-(-1x)-6+5+8+10=0
We get rid of parentheses
3x-10x+6x+1x-6+5+8+10=0
We add all the numbers together, and all the variables
17!=0
There is no solution for this equation
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