3(x-2)-4=-3(x+3)-7

Solution for 3(x-2)-4=-3(x+3)-7 equation:

3(x-2)-4=-3(x+3)-7

We move all terms to the left:

3(x-2)-4-(-3(x+3)-7)=0

We multiply parentheses

3x-(-3(x+3)-7)-6-4=0


We calculate terms in parentheses: -(-3(x+3)-7), so:

-3(x+3)-7

We multiply parentheses

-3x-9-7

We add all the numbers together, and all the variables

-3x-16

Back to the equation:

-(-3x-16)


We add all the numbers together, and all the variables

3x-(-3x-16)-10=0

We get rid of parentheses

3x+3x+16-10=0

We add all the numbers together, and all the variables

6x+6=0

We move all terms containing x to the left, all other terms to the right

6x=-6

x=-6/6

x=-1