3(x-2)-(4x-7)=3(4x-1)

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Solution for 3(x-2)-(4x-7)=3(4x-1) equation: 



3(x-2)-(4x-7)=3(4x-1)

We move all terms to the left:

3(x-2)-(4x-7)-(3(4x-1))=0

We multiply parentheses

3x-(4x-7)-(3(4x-1))-6=0

We get rid of parentheses

3x-4x-(3(4x-1))+7-6=0



We calculate terms in parentheses: -(3(4x-1)), so:

3(4x-1)

We multiply parentheses

12x-3

Back to the equation:

-(12x-3)



We add all the numbers together, and all the variables

-1x-(12x-3)+1=0

We get rid of parentheses

-1x-12x+3+1=0

We add all the numbers together, and all the variables

-13x+4=0

We move all terms containing x to the left, all other terms to the right

-13x=-4

x=-4/-13

x=4/13

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