3(x-2)+x=-4-(x+5)

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Solution for 3(x-2)+x=-4-(x+5) equation: 



3(x-2)+x=-4-(x+5)

We move all terms to the left:

3(x-2)+x-(-4-(x+5))=0

We add all the numbers together, and all the variables

x+3(x-2)-(-4-(x+5))=0

We multiply parentheses

x+3x-(-4-(x+5))-6=0



We calculate terms in parentheses: -(-4-(x+5)), so:

-4-(x+5)

determiningTheFunctionDomain
-(x+5)-4

We get rid of parentheses

-x-5-4

We add all the numbers together, and all the variables

-1x-9

Back to the equation:

-(-1x-9)



We add all the numbers together, and all the variables

4x-(-1x-9)-6=0

We get rid of parentheses

4x+1x+9-6=0

We add all the numbers together, and all the variables

5x+3=0

We move all terms containing x to the left, all other terms to the right

5x=-3

x=-3/5

x=-3/5

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