3(x-2)+x+4=10

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Solution for 3(x-2)+x+4=10 equation: 



3(x-2)+x+4=10

We move all terms to the left:

3(x-2)+x+4-(10)=0

We add all the numbers together, and all the variables

x+3(x-2)-6=0

We multiply parentheses

x+3x-6-6=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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