3(x-2)+8=4x(2)+(3x+4)

Solution for 3(x-2)+8=4x(2)+(3x+4) equation:

3(x-2)+8=4x(2)+(3x+4)

We move all terms to the left:

3(x-2)+8-(4x(2)+(3x+4))=0

We multiply parentheses

3x-(4x2+(3x+4))-6+8=0


We calculate terms in parentheses: -(4x2+(3x+4)), so:

4x2+(3x+4)

We add all the numbers together, and all the variables

4x^2+(3x+4)

We get rid of parentheses

4x^2+3x+4

Back to the equation:

-(4x^2+3x+4)


We add all the numbers together, and all the variables

3x-(4x^2+3x+4)+2=0

We get rid of parentheses

-4x^2+3x-3x-4+2=0

We add all the numbers together, and all the variables

-4x^2-2=0

a = -4; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·(-4)·(-2)
Δ = -32
Delta is less than zero, so there is no solution for the equation