3(x-2)+4x=7(x-1)+1

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Solution for 3(x-2)+4x=7(x-1)+1 equation: 



3(x-2)+4x=7(x-1)+1

We move all terms to the left:

3(x-2)+4x-(7(x-1)+1)=0

We add all the numbers together, and all the variables

4x+3(x-2)-(7(x-1)+1)=0

We multiply parentheses

4x+3x-(7(x-1)+1)-6=0



We calculate terms in parentheses: -(7(x-1)+1), so:

7(x-1)+1

We multiply parentheses

7x-7+1

We add all the numbers together, and all the variables

7x-6

Back to the equation:

-(7x-6)



We add all the numbers together, and all the variables

7x-(7x-6)-6=0

We get rid of parentheses

7x-7x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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