3(x-2)+4x=10(x+)

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Solution for 3(x-2)+4x=10(x+) equation:



3(x-2)+4x=10(x+)
We move all terms to the left:
3(x-2)+4x-(10(x+))=0
We add all the numbers together, and all the variables
3(x-2)+4x-(10(+x))=0
We add all the numbers together, and all the variables
4x+3(x-2)-(10(+x))=0
We multiply parentheses
4x+3x-(10(+x))-6=0
We calculate terms in parentheses: -(10(+x)), so:
10(+x)
We multiply parentheses
10x
Back to the equation:
-(10x)
We add all the numbers together, and all the variables
-3x-6=0
We move all terms containing x to the left, all other terms to the right
-3x=6
x=6/-3
x=-2

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