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3(x-2)+4x=(x+1)
We move all terms to the left:
3(x-2)+4x-((x+1))=0
We add all the numbers together, and all the variables
4x+3(x-2)-((x+1))=0
We multiply parentheses
4x+3x-((x+1))-6=0
We calculate terms in parentheses: -((x+1)), so:We add all the numbers together, and all the variables
(x+1)
We get rid of parentheses
x+1
Back to the equation:
-(x+1)
7x-(x+1)-6=0
We get rid of parentheses
7x-x-1-6=0
We add all the numbers together, and all the variables
6x-7=0
We move all terms containing x to the left, all other terms to the right
6x=7
x=7/6
x=1+1/6
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