3(x-2)+4(x+1)=-16

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Solution for 3(x-2)+4(x+1)=-16 equation: 



3(x-2)+4(x+1)=-16

We move all terms to the left:

3(x-2)+4(x+1)-(-16)=0

We add all the numbers together, and all the variables

3(x-2)+4(x+1)+16=0

We multiply parentheses

3x+4x-6+4+16=0

We add all the numbers together, and all the variables

7x+14=0

We move all terms containing x to the left, all other terms to the right

7x=-14

x=-14/7

x=-2

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