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3(x-2)+2x=2(x-5)
We move all terms to the left:
3(x-2)+2x-(2(x-5))=0
We add all the numbers together, and all the variables
2x+3(x-2)-(2(x-5))=0
We multiply parentheses
2x+3x-(2(x-5))-6=0
We calculate terms in parentheses: -(2(x-5)), so:We add all the numbers together, and all the variables
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
5x-(2x-10)-6=0
We get rid of parentheses
5x-2x+10-6=0
We add all the numbers together, and all the variables
3x+4=0
We move all terms containing x to the left, all other terms to the right
3x=-4
x=-4/3
x=-1+1/3
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