3(x-2)+2=2(x-2)+x

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Solution for 3(x-2)+2=2(x-2)+x equation:


Simplifying
3(x + -2) + 2 = 2(x + -2) + x

Reorder the terms:
3(-2 + x) + 2 = 2(x + -2) + x
(-2 * 3 + x * 3) + 2 = 2(x + -2) + x
(-6 + 3x) + 2 = 2(x + -2) + x

Reorder the terms:
-6 + 2 + 3x = 2(x + -2) + x

Combine like terms: -6 + 2 = -4
-4 + 3x = 2(x + -2) + x

Reorder the terms:
-4 + 3x = 2(-2 + x) + x
-4 + 3x = (-2 * 2 + x * 2) + x
-4 + 3x = (-4 + 2x) + x

Combine like terms: 2x + x = 3x
-4 + 3x = -4 + 3x

Add '4' to each side of the equation.
-4 + 4 + 3x = -4 + 4 + 3x

Combine like terms: -4 + 4 = 0
0 + 3x = -4 + 4 + 3x
3x = -4 + 4 + 3x

Combine like terms: -4 + 4 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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