3(x-2)+2(4-x)=16

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Solution for 3(x-2)+2(4-x)=16 equation:



3(x-2)+2(4-x)=16
We move all terms to the left:
3(x-2)+2(4-x)-(16)=0
We add all the numbers together, and all the variables
3(x-2)+2(-1x+4)-16=0
We multiply parentheses
3x-2x-6+8-16=0
We add all the numbers together, and all the variables
x-14=0
We move all terms containing x to the left, all other terms to the right
x=14

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