3(x-2)+1=x+2(4+x)

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Solution for 3(x-2)+1=x+2(4+x) equation:



3(x-2)+1=x+2(4+x)
We move all terms to the left:
3(x-2)+1-(x+2(4+x))=0
We add all the numbers together, and all the variables
3(x-2)-(x+2(x+4))+1=0
We multiply parentheses
3x-(x+2(x+4))-6+1=0
We calculate terms in parentheses: -(x+2(x+4)), so:
x+2(x+4)
We multiply parentheses
x+2x+8
We add all the numbers together, and all the variables
3x+8
Back to the equation:
-(3x+8)
We add all the numbers together, and all the variables
3x-(3x+8)-5=0
We get rid of parentheses
3x-3x-8-5=0
We add all the numbers together, and all the variables
-13!=0
There is no solution for this equation

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