3(x-2)+1=6x-3(2+x)

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Solution for 3(x-2)+1=6x-3(2+x) equation: 



3(x-2)+1=6x-3(2+x)

We move all terms to the left:

3(x-2)+1-(6x-3(2+x))=0

We add all the numbers together, and all the variables

3(x-2)-(6x-3(x+2))+1=0

We multiply parentheses

3x-(6x-3(x+2))-6+1=0



We calculate terms in parentheses: -(6x-3(x+2)), so:

6x-3(x+2)

We multiply parentheses

6x-3x-6

We add all the numbers together, and all the variables

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

3x-(3x-6)-5=0

We get rid of parentheses

3x-3x+6-5=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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