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3(x-2)+1=2x-5+x
We move all terms to the left:
3(x-2)+1-(2x-5+x)=0
We add all the numbers together, and all the variables
3(x-2)-(3x-5)+1=0
We multiply parentheses
3x-(3x-5)-6+1=0
We get rid of parentheses
3x-3x+5-6+1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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