3(x-2)+1=2+x-4)+x+13

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Solution for 3(x-2)+1=2+x-4)+x+13 equation: 



3(x-2)+1=2+x-4)+x+13

We move all terms to the left:

3(x-2)+1-(2+x-4)+x+13)=0

We add all the numbers together, and all the variables

3(x-2)-(x-2)+x+1+13)=0

We add all the numbers together, and all the variables

x+3(x-2)-(x-2)=0

We multiply parentheses

x+3x-(x-2)-6=0

We get rid of parentheses

x+3x-x+2-6=0

We add all the numbers together, and all the variables

3x-4=0

We move all terms containing x to the left, all other terms to the right

3x=4

x=4/3

x=1+1/3

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