3(x-2)+10=5(x-4)+2x

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Solution for 3(x-2)+10=5(x-4)+2x equation: 



3(x-2)+10=5(x-4)+2x

We move all terms to the left:

3(x-2)+10-(5(x-4)+2x)=0

We multiply parentheses

3x-(5(x-4)+2x)-6+10=0



We calculate terms in parentheses: -(5(x-4)+2x), so:

5(x-4)+2x

We add all the numbers together, and all the variables

2x+5(x-4)

We multiply parentheses

2x+5x-20

We add all the numbers together, and all the variables

7x-20

Back to the equation:

-(7x-20)



We add all the numbers together, and all the variables

3x-(7x-20)+4=0

We get rid of parentheses

3x-7x+20+4=0

We add all the numbers together, and all the variables

-4x+24=0

We move all terms containing x to the left, all other terms to the right

-4x=-24

x=-24/-4

x=+6

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