3(x-2)+10=2(x-5)+18

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Solution for 3(x-2)+10=2(x-5)+18 equation: 



3(x-2)+10=2(x-5)+18

We move all terms to the left:

3(x-2)+10-(2(x-5)+18)=0

We multiply parentheses

3x-(2(x-5)+18)-6+10=0



We calculate terms in parentheses: -(2(x-5)+18), so:

2(x-5)+18

We multiply parentheses

2x-10+18

We add all the numbers together, and all the variables

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

3x-(2x+8)+4=0

We get rid of parentheses

3x-2x-8+4=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

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