3(x-2)+(x+1)=14

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Solution for 3(x-2)+(x+1)=14 equation:



3(x-2)+(x+1)=14
We move all terms to the left:
3(x-2)+(x+1)-(14)=0
We multiply parentheses
3x+(x+1)-6-14=0
We get rid of parentheses
3x+x+1-6-14=0
We add all the numbers together, and all the variables
4x-19=0
We move all terms containing x to the left, all other terms to the right
4x=19
x=19/4
x=4+3/4

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