3(x-15)+(x+16)=6(x-1)-4x-1

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Solution for 3(x-15)+(x+16)=6(x-1)-4x-1 equation: 



3(x-15)+(x+16)=6(x-1)-4x-1

We move all terms to the left:

3(x-15)+(x+16)-(6(x-1)-4x-1)=0

We multiply parentheses

3x+(x+16)-(6(x-1)-4x-1)-45=0

We get rid of parentheses

3x+x-(6(x-1)-4x-1)+16-45=0



We calculate terms in parentheses: -(6(x-1)-4x-1), so:

6(x-1)-4x-1

We add all the numbers together, and all the variables

-4x+6(x-1)-1

We multiply parentheses

-4x+6x-6-1

We add all the numbers together, and all the variables

2x-7

Back to the equation:

-(2x-7)



We add all the numbers together, and all the variables

4x-(2x-7)-29=0

We get rid of parentheses

4x-2x+7-29=0

We add all the numbers together, and all the variables

2x-22=0

We move all terms containing x to the left, all other terms to the right

2x=22

x=22/2

x=11

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