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3(x-12)=2(x+7)
We move all terms to the left:
3(x-12)-(2(x+7))=0
We multiply parentheses
3x-(2(x+7))-36=0
We calculate terms in parentheses: -(2(x+7)), so:We get rid of parentheses
2(x+7)
We multiply parentheses
2x+14
Back to the equation:
-(2x+14)
3x-2x-14-36=0
We add all the numbers together, and all the variables
x-50=0
We move all terms containing x to the left, all other terms to the right
x=50
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