3(x-11)+5=2(x-2)+x-20=

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Solution for 3(x-11)+5=2(x-2)+x-20= equation: 



3(x-11)+5=2(x-2)+x-20=

We move all terms to the left:

3(x-11)+5-(2(x-2)+x-20)=0

We multiply parentheses

3x-(2(x-2)+x-20)-33+5=0



We calculate terms in parentheses: -(2(x-2)+x-20), so:

2(x-2)+x-20

We add all the numbers together, and all the variables

x+2(x-2)-20

We multiply parentheses

x+2x-4-20

We add all the numbers together, and all the variables

3x-24

Back to the equation:

-(3x-24)



We add all the numbers together, and all the variables

3x-(3x-24)-28=0

We get rid of parentheses

3x-3x+24-28=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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