3(x-1/2)=5(x+2/3)+4x-1

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Solution for 3(x-1/2)=5(x+2/3)+4x-1 equation: 



3(x-1/2)=5(x+2/3)+4x-1

We move all terms to the left:

3(x-1/2)-(5(x+2/3)+4x-1)=0



Domain of the equation: 3)+4x-1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3(+x-1/2)-(5(+x+2/3)+4x-1)=0

We multiply parentheses

3x-(5(+x+2/3)+4x-1)-1/2*3=0

We calculate fractions


3x+(-(5(+x+2*2*3)/3+4x-1)*2*3)+(-3x)/3+4x-1)*2*3)=0



We calculate terms in parentheses: +(-(5(+x+2*2*3)/3+4x-1)*2*3), so:

-(5(+x+2*2*3)/3+4x-1)*2*3

We add all the numbers together, and all the variables

-(5(x+12)/3+4x-1)*2*3

We multiply all the terms by the denominator


-(5(x+12)



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Back to the equation:

+(-(5(x+12))



We multiply all the terms by the denominator


3x*3+4x-1)*2*3)+(-(5(x+12))+(-3x)=0

We add all the numbers together, and all the variables

4x+3x*3-1)*2*3)+(-(5(x+12))+(-3x)=0

Wy multiply elements

4x+9x-1)*2*3)+(-(5(x+12))+(-3x)=0

We add all the numbers together, and all the variables

13x-1)*2*3)+(-(5(x+12))+(-3x)=0

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