3(x-1)=4x+2-3(2-x)

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Solution for 3(x-1)=4x+2-3(2-x) equation: 



3(x-1)=4x+2-3(2-x)

We move all terms to the left:

3(x-1)-(4x+2-3(2-x))=0

We add all the numbers together, and all the variables

3(x-1)-(4x+2-3(-1x+2))=0

We multiply parentheses

3x-(4x+2-3(-1x+2))-3=0



We calculate terms in parentheses: -(4x+2-3(-1x+2)), so:

4x+2-3(-1x+2)

determiningTheFunctionDomain
4x-3(-1x+2)+2

We multiply parentheses

4x+3x-6+2

We add all the numbers together, and all the variables

7x-4

Back to the equation:

-(7x-4)



We get rid of parentheses

3x-7x+4-3=0

We add all the numbers together, and all the variables

-4x+1=0

We move all terms containing x to the left, all other terms to the right

-4x=-1

x=-1/-4

x=1/4

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