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3(x-1)=2(2+x)
We move all terms to the left:
3(x-1)-(2(2+x))=0
We add all the numbers together, and all the variables
3(x-1)-(2(x+2))=0
We multiply parentheses
3x-(2(x+2))-3=0
We calculate terms in parentheses: -(2(x+2)), so:We get rid of parentheses
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
3x-2x-4-3=0
We add all the numbers together, and all the variables
x-7=0
We move all terms containing x to the left, all other terms to the right
x=7
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