3(x-1)-4(x-2)=6(2x+3)

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Solution for 3(x-1)-4(x-2)=6(2x+3) equation: 



3(x-1)-4(x-2)=6(2x+3)

We move all terms to the left:

3(x-1)-4(x-2)-(6(2x+3))=0

We multiply parentheses

3x-4x-(6(2x+3))-3+8=0



We calculate terms in parentheses: -(6(2x+3)), so:

6(2x+3)

We multiply parentheses

12x+18

Back to the equation:

-(12x+18)



We add all the numbers together, and all the variables

-1x-(12x+18)+5=0

We get rid of parentheses

-1x-12x-18+5=0

We add all the numbers together, and all the variables

-13x-13=0

We move all terms containing x to the left, all other terms to the right

-13x=13

x=13/-13

x=-1

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