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3(x-1)-2=2(x+2)
We move all terms to the left:
3(x-1)-2-(2(x+2))=0
We multiply parentheses
3x-(2(x+2))-3-2=0
We calculate terms in parentheses: -(2(x+2)), so:We add all the numbers together, and all the variables
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
3x-(2x+4)-5=0
We get rid of parentheses
3x-2x-4-5=0
We add all the numbers together, and all the variables
x-9=0
We move all terms containing x to the left, all other terms to the right
x=9
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