3(x-1)-2(x+1)=(x+1)-2(x-1)

Solution for 3(x-1)-2(x+1)=(x+1)-2(x-1) equation:

3(x-1)-2(x+1)=(x+1)-2(x-1)

We move all terms to the left:

3(x-1)-2(x+1)-((x+1)-2(x-1))=0

We multiply parentheses

3x-2x-((x+1)-2(x-1))-3-2=0


We calculate terms in parentheses: -((x+1)-2(x-1)), so:

(x+1)-2(x-1)

We multiply parentheses

(x+1)-2x+2

We get rid of parentheses

x-2x+1+2

We add all the numbers together, and all the variables

-1x+3

Back to the equation:

-(-1x+3)


We add all the numbers together, and all the variables

x-(-1x+3)-5=0

We get rid of parentheses

x+1x-3-5=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4