3(x-1)+x=-2(1-x)+x

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Solution for 3(x-1)+x=-2(1-x)+x equation: 



3(x-1)+x=-2(1-x)+x

We move all terms to the left:

3(x-1)+x-(-2(1-x)+x)=0

We add all the numbers together, and all the variables

3(x-1)+x-(-2(-1x+1)+x)=0

We add all the numbers together, and all the variables

x+3(x-1)-(-2(-1x+1)+x)=0

We multiply parentheses

x+3x-(-2(-1x+1)+x)-3=0



We calculate terms in parentheses: -(-2(-1x+1)+x), so:

-2(-1x+1)+x

We add all the numbers together, and all the variables

x-2(-1x+1)

We multiply parentheses

x+2x-2

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

4x-(3x-2)-3=0

We get rid of parentheses

4x-3x+2-3=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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