3(x-1)+x2=2(2x+1)+3

Solution for 3(x-1)+x2=2(2x+1)+3 equation:

3(x-1)+x2=2(2x+1)+3

We move all terms to the left:

3(x-1)+x2-(2(2x+1)+3)=0

We add all the numbers together, and all the variables

x^2+3(x-1)-(2(2x+1)+3)=0

We multiply parentheses

x^2+3x-(2(2x+1)+3)-3=0


We calculate terms in parentheses: -(2(2x+1)+3), so:

2(2x+1)+3

We multiply parentheses

4x+2+3

We add all the numbers together, and all the variables

4x+5

Back to the equation:

-(4x+5)


We get rid of parentheses

x^2+3x-4x-5-3=0

We add all the numbers together, and all the variables

x^2-1x-8=0

a = 1; b = -1; c = -8;
Δ = b2-4ac
Δ = -12-4·1·(-8)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{33}}{2*1}=\frac{1-\sqrt{33}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{33}}{2*1}=\frac{1+\sqrt{33}}{2}
$