3(x-1)+2x=3(x+1)+2

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Solution for 3(x-1)+2x=3(x+1)+2 equation: 



3(x-1)+2x=3(x+1)+2

We move all terms to the left:

3(x-1)+2x-(3(x+1)+2)=0

We add all the numbers together, and all the variables

2x+3(x-1)-(3(x+1)+2)=0

We multiply parentheses

2x+3x-(3(x+1)+2)-3=0



We calculate terms in parentheses: -(3(x+1)+2), so:

3(x+1)+2

We multiply parentheses

3x+3+2

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We add all the numbers together, and all the variables

5x-(3x+5)-3=0

We get rid of parentheses

5x-3x-5-3=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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