3(x-1)+2(3-2x)=6(x+4)-7

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Solution for 3(x-1)+2(3-2x)=6(x+4)-7 equation: 



3(x-1)+2(3-2x)=6(x+4)-7

We move all terms to the left:

3(x-1)+2(3-2x)-(6(x+4)-7)=0

We add all the numbers together, and all the variables

3(x-1)+2(-2x+3)-(6(x+4)-7)=0

We multiply parentheses

3x-4x-(6(x+4)-7)-3+6=0



We calculate terms in parentheses: -(6(x+4)-7), so:

6(x+4)-7

We multiply parentheses

6x+24-7

We add all the numbers together, and all the variables

6x+17

Back to the equation:

-(6x+17)



We add all the numbers together, and all the variables

-1x-(6x+17)+3=0

We get rid of parentheses

-1x-6x-17+3=0

We add all the numbers together, and all the variables

-7x-14=0

We move all terms containing x to the left, all other terms to the right

-7x=14

x=14/-7

x=-2

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