3(x-1)+1=6-(x-4)

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Solution for 3(x-1)+1=6-(x-4) equation: 



3(x-1)+1=6-(x-4)

We move all terms to the left:

3(x-1)+1-(6-(x-4))=0

We multiply parentheses

3x-(6-(x-4))-3+1=0



We calculate terms in parentheses: -(6-(x-4)), so:

6-(x-4)

determiningTheFunctionDomain
-(x-4)+6

We get rid of parentheses

-x+4+6

We add all the numbers together, and all the variables

-1x+10

Back to the equation:

-(-1x+10)



We add all the numbers together, and all the variables

3x-(-1x+10)-2=0

We get rid of parentheses

3x+1x-10-2=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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