3(x-1)+1-5x=7-2(x+4)

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Solution for 3(x-1)+1-5x=7-2(x+4) equation: 



3(x-1)+1-5x=7-2(x+4)

We move all terms to the left:

3(x-1)+1-5x-(7-2(x+4))=0

We add all the numbers together, and all the variables

-5x+3(x-1)-(7-2(x+4))+1=0

We multiply parentheses

-5x+3x-(7-2(x+4))-3+1=0



We calculate terms in parentheses: -(7-2(x+4)), so:

7-2(x+4)

determiningTheFunctionDomain
-2(x+4)+7

We multiply parentheses

-2x-8+7

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We add all the numbers together, and all the variables

-2x-(-2x-1)-2=0

We get rid of parentheses

-2x+2x+1-2=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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