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3(x-1)(6x+18)=0
We multiply parentheses ..
3(+6x^2+18x-6x-18)=0
We multiply parentheses
18x^2+54x-18x-54=0
We add all the numbers together, and all the variables
18x^2+36x-54=0
a = 18; b = 36; c = -54;
Δ = b2-4ac
Δ = 362-4·18·(-54)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-72}{2*18}=\frac{-108}{36} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+72}{2*18}=\frac{36}{36} =1 $
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