3(x+iy)-i(x-iy)=16

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Solution for 3(x+iy)-i(x-iy)=16 equation: 


Simplifying
3(x + iy) + -1i(x + -1iy) = 16

Reorder the terms:
3(iy + x) + -1i(x + -1iy) = 16
(iy * 3 + x * 3) + -1i(x + -1iy) = 16
(3iy + 3x) + -1i(x + -1iy) = 16

Reorder the terms:
3iy + 3x + -1i(-1iy + x) = 16
3iy + 3x + (-1iy * -1i + x * -1i) = 16

Reorder the terms:
3iy + 3x + (-1ix + 1i2y) = 16
3iy + 3x + (-1ix + 1i2y) = 16

Reorder the terms:
-1ix + 3iy + 1i2y + 3x = 16

Solving
-1ix + 3iy + 1i2y + 3x = 16

Solving for variable 'i'.

Reorder the terms:
-16 + -1ix + 3iy + 1i2y + 3x = 16 + -16

Combine like terms: 16 + -16 = 0
-16 + -1ix + 3iy + 1i2y + 3x = 0

The solution to this equation could not be determined.

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