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3(x+9)=5/4x
We move all terms to the left:
3(x+9)-(5/4x)=0
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3(x+9)-(+5/4x)=0
We multiply parentheses
3x-(+5/4x)+27=0
We get rid of parentheses
3x-5/4x+27=0
We multiply all the terms by the denominator
3x*4x+27*4x-5=0
Wy multiply elements
12x^2+108x-5=0
a = 12; b = 108; c = -5;
Δ = b2-4ac
Δ = 1082-4·12·(-5)
Δ = 11904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11904}=\sqrt{64*186}=\sqrt{64}*\sqrt{186}=8\sqrt{186}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(108)-8\sqrt{186}}{2*12}=\frac{-108-8\sqrt{186}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(108)+8\sqrt{186}}{2*12}=\frac{-108+8\sqrt{186}}{24} $
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