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3(x+6)=12(x+1)+3
We move all terms to the left:
3(x+6)-(12(x+1)+3)=0
We multiply parentheses
3x-(12(x+1)+3)+18=0
We calculate terms in parentheses: -(12(x+1)+3), so:We get rid of parentheses
12(x+1)+3
We multiply parentheses
12x+12+3
We add all the numbers together, and all the variables
12x+15
Back to the equation:
-(12x+15)
3x-12x-15+18=0
We add all the numbers together, and all the variables
-9x+3=0
We move all terms containing x to the left, all other terms to the right
-9x=-3
x=-3/-9
x=1/3
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