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3(x+5)=6(2x-6)+3
We move all terms to the left:
3(x+5)-(6(2x-6)+3)=0
We multiply parentheses
3x-(6(2x-6)+3)+15=0
We calculate terms in parentheses: -(6(2x-6)+3), so:We get rid of parentheses
6(2x-6)+3
We multiply parentheses
12x-36+3
We add all the numbers together, and all the variables
12x-33
Back to the equation:
-(12x-33)
3x-12x+33+15=0
We add all the numbers together, and all the variables
-9x+48=0
We move all terms containing x to the left, all other terms to the right
-9x=-48
x=-48/-9
x=5+1/3
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