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3(x+5)=2(x+5)+x+5
We move all terms to the left:
3(x+5)-(2(x+5)+x+5)=0
We multiply parentheses
3x-(2(x+5)+x+5)+15=0
We calculate terms in parentheses: -(2(x+5)+x+5), so:We get rid of parentheses
2(x+5)+x+5
We add all the numbers together, and all the variables
x+2(x+5)+5
We multiply parentheses
x+2x+10+5
We add all the numbers together, and all the variables
3x+15
Back to the equation:
-(3x+15)
3x-3x-15+15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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