3(x+5)=2(3x-2)+7

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Solution for 3(x+5)=2(3x-2)+7 equation: 



3(x+5)=2(3x-2)+7

We move all terms to the left:

3(x+5)-(2(3x-2)+7)=0

We multiply parentheses

3x-(2(3x-2)+7)+15=0



We calculate terms in parentheses: -(2(3x-2)+7), so:

2(3x-2)+7

We multiply parentheses

6x-4+7

We add all the numbers together, and all the variables

6x+3

Back to the equation:

-(6x+3)



We get rid of parentheses

3x-6x-3+15=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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