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3(x+5)=2(3x+12)=
We move all terms to the left:
3(x+5)-(2(3x+12))=0
We multiply parentheses
3x-(2(3x+12))+15=0
We calculate terms in parentheses: -(2(3x+12)), so:We get rid of parentheses
2(3x+12)
We multiply parentheses
6x+24
Back to the equation:
-(6x+24)
3x-6x-24+15=0
We add all the numbers together, and all the variables
-3x-9=0
We move all terms containing x to the left, all other terms to the right
-3x=9
x=9/-3
x=-3
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