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3(x+5)=(2x-6)+3
We move all terms to the left:
3(x+5)-((2x-6)+3)=0
We multiply parentheses
3x-((2x-6)+3)+15=0
We calculate terms in parentheses: -((2x-6)+3), so:We get rid of parentheses
(2x-6)+3
We get rid of parentheses
2x-6+3
We add all the numbers together, and all the variables
2x-3
Back to the equation:
-(2x-3)
3x-2x+3+15=0
We add all the numbers together, and all the variables
x+18=0
We move all terms containing x to the left, all other terms to the right
x=-18
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